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🧪 Solutions & Colligative Properties

Solutions chemistry bridges molecular thermodynamic interactions with observable bulk colligative phenomena. Advanced examination questions test positive/negative deviations from Raoult's law, vapor-liquid equilibrium curves (Pxy), abnormal molar masses, and degree of association/dissociation (α).


1. 🍶 Vapor Pressure & Raoult's Law

1.1 Ideal Binary Solutions

For two volatile miscible liquids A and B:

PA=PAxA,PB=PBxBPtotal=PA+PB=PAxA+PB(1xA)=PB+(PAPB)xA

Composition of Vapor Phase in Equilibrium with Liquid:

yA=PAPtotal=PAxAPtotal,yB=PBPtotal=PBxBPtotal1Ptotal=yAPA+yBPB

2. 📊 Non-Ideal Solutions & Azeotropes

PropertyIdeal SolutionsPositive Deviation (DeltaHmix>0)Negative Deviation (DeltaHmix<0)
Intermolecular ForcesAB=AA=BBAB<AA,BB (Weaker)AB>AA,BB (Stronger, e.g. H-bonding)
Vapor PressureP=PAxA+PBxBP>PidealP<Pideal
Enthalpy of MixingΔHmix=0ΔHmix>0 (Endothermic)ΔHmix<0 (Exothermic)
Volume of MixingΔVmix=0ΔVmix>0 (Expansion)ΔVmix<0 (Contraction)
Azeotropic BehaviorNo azeotrope formedMinimum Boiling Azeotrope (e.g. 95.6% Ethanol + Water)Maximum Boiling Azeotrope (e.g. 68% HNO3+32% H2O)
Classic ExamplesBenzene + Toluene, n-Hexane + n-HeptaneEthanol + Acetone, CS2+AcetoneChloroform + Acetone, HCl+H2O

3. 🎯 The 4 Colligative Properties

Colligative properties depend strictly on the number of solute particles in solution, not on their chemical identity.

3.1 Relative Lowering of Vapor Pressure (RLVP)

PPP=xsolute=n2n1+n2PPP=n2n1=w2/M2w1/M1

3.2 Elevation of Boiling Point (Ebullioscopy)

ΔTb=TbTb=iKbmKb=RTb2Msolvent1000ΔHvap=RTb21000Lv(Kb(water)=0.52 K kg/mol)

3.3 Depression of Freezing Point (Cryoscopy)

ΔTf=TfTf=iKfmKf=RTf2Msolvent1000ΔHfus=RTf21000Lf(Kf(water)=1.86 K kg/mol)

3.4 Osmotic Pressure (Π)

Π=iCRT=i(nV)RT
  • Isotonic Solutions: Π1=Π2i1C1=i2C2 (at equal T).
  • Reverse Osmosis: When applied external pressure Pext>Π, pure solvent flows from concentrated solution to pure solvent side through semi-permeable membrane.

4. 🧮 Van 't Hoff Factor (i) & Degree of Association / Dissociation

i=Observed Colligative PropertyTheoretical Colligative Property=Theoretical Molar MassObserved Molar Mass=Total Moles After Dissociation/AssociationInitial Moles
  1. For Dissociation (AnnA):α=i1n1i=1+(n1)αExample: For K4[Fe(CN)6]n=5. If α=80%=0.8i=1+4(0.8)=4.2.
  2. For Association (nAAn, e.g. Benzoic acid dimerizing in Benzene):α=1i11/n=n(1i)n1i=1(11n)αFor complete dimerization (n=2,α=1) i=0.5.